Date:         Mon, 24 Jul 2000 02:17:34 PDT
Reply-To:     Mark Dorm <mark_hb@hotmail.com>
Sender:       Vanagon Mailing List <vanagon@gerry.vanagon.com>
From:         Mark Dorm <mark_hb@hotmail.com>
Subject:      Re: Weep No More For Me
Comments: To: djs@gene.com
Content-Type: text/plain; format=flowed

can you have two water pumps running at the same time?

>From: Daniel Schmitz <djs@gene.com>
>Reply-To: Daniel Schmitz <djs@gene.com>
>To: vanagon@GERRY.VANAGON.COM
>Subject: Re: Weep No More For Me
>Date: Wed, 12 Jul 2000 19:30:04 -0700
>
>Having failed to progress in mathematics past college algebra, I am hard
>pressed
>to ascertain the answers to the following questions:
>
>If the coolant was pumped uphill and stayed there, and the pump continued
>to
>pump, wouldn't something near the front of the van eventually burst and
>make a
>mess? And, based on the original poster's assumption that the water pump
>has to
>work relatively hard to pump coolant uphill, would it do less real work if
>the
>van were constantly driven downhill?
>
>These are questions for which a differential equation appears unequal to
>the
>task.
>
>Dan
>'87 Westfalia, with optional, down-slope-optimized cooling system (parked
>on a
>hill)
>'82 Adventurewagen, with hardly any cooling system at all
>'75 Porsche 914, same as above
>
>
>"John D. Stepto" wrote:
>
> > -----Original Message-----
> > From: The Gunnings <ngunn@landmarknet.net>
> > To: vanagon@GERRY.VANAGON.COM <vanagon@GERRY.VANAGON.COM>
> > Date: Wednesday, July 12, 2000 1:24 PM
> > Subject: Weep No More For Me
> >
> > >
> > >One of the weakest links in the waterboxer design is
> > >the is the constant strain on the waterpump to push coolant uphill to
>the
> > >front radiator.
> >
> > Actually, the pump is straining to push coolant uphill because the
>coolant
> > turns around and goes back down hill and pulls the equal amount back up.
> > Its a closed system and energy potential (mass x gravity x height) is
>almost
> > equal at the pump. If the coolant was pumped uphill and stayed there,
>then
> > the work done by the pump would be the the (mass the coolant moved) x
> > gravity x (the height from the pump to the top of the coolant level).
>Of
> > coarse, the level is constantly changing and you would end up with a
>simple
> > differential equation.
> >
> > Is it Friday yet?
> >
> > John
>
>--
>Dan
>__________________________________________________
>Dan Schmitz - Genentech Automation Engineering
>djs@gene.com (650) 225-6119
>__________________________________________________
>
>"I'll so offend to make offense a skill
>Redeeming time when men least think I will"
>
>W. Shakespeare
>Henry IV, Part 1

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