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Date:         Fri, 2 Nov 2001 08:50:40 -0800
Reply-To:     Edward Nutter <eanutter@POSTOFFICE.PACBELL.NET>
Sender:       Vanagon Mailing List <vanagon@gerry.vanagon.com>
From:         Edward Nutter <eanutter@POSTOFFICE.PACBELL.NET>
Subject:      Re: measuring pressure inside of a propane tank?
Comments: To: Matthew Pollard <poll7356@UIDAHO.EDU>
Content-type: text/plain; x-mac-creator=4D4F5353; x-mac-type=54455854;
              charset=us-ascii

My recollection is that propane and butane liquify when they are compressed to whatever their vapor pressures are at a particular temperature. There they sit, with some liquid going to gas as temperature rises, and recondensing as temperature drops.

Matthew Pollard wrote:

> My thermodynamics says that you can measure the pressure by mass. Weight > an empty tank and a full tank. The difference is the mass of the propane > in there. Now comes some math... > pressureXvolume=molesXgas constantXtemp > you know v, n, r, and t. > n=moles= mass of gas/formula weight of gas (propane is 44grams/mole) > v=volume of the clinder. Lets say 1L > R=gas constant=0.0821 L*atm/mol*Kelvin > Temp=298K (or about room temp). > > So for 1000grams of gas, that corresponds to.... 556atm which is about > 8173 psi. Yikes. that is high. Hmmm, somebody check my math here. > > This is for an ideal gas though.... Propane is NOT ideal, esp at high > pressures. We'll need the van der waals equation for a better answer. > > But that gives you an idea that we have a lot of pressure here! > > ok, back to work > m

[snip]


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