Ok, i'll help out there- 1) how long is the bus (the hypothenuse)? the height to raise the bus is like this Height=(length of bus in inches)*sine(angle) So for a bus that is 16' long and 15 degrees up... 16x12xsin(15)=49.6932" (or -> 16' x 12" x .258819=49.6"=4.14' this is 4'! lets go backwards- lets rais the bus 30" instead... what angle? sin(X)=30'/192" sin^-1(30/192)=X X=8.98degrees -->sin^1 is the inverse sine. on a calculator is is usually shift-sin (the funciton that is inverse of sine) got it? cheers Matthew SOH-CAH-TOA Matthew Pollard "Racing with the wind and flirting with death Dept. Of Chemistry So have a cup of coffee and catch your breath" University of Idaho www.uidaho.edu/~poll7356
On Sat, 24 Nov 2001, Jere Hawn wrote: > Hi All, > > I'm improving my "bleeding the cooling system" flow chart and I am at the > raise the front by 15 degrees. Being very weak in trigonometry and > spelling... how many inches does the front end need to come up to make 15 > degrees. > > Sorry I don't have the wheel base dimensions. > > Once I've finish with this one part it will be available for distribution > for those wishing a copy please p-mail > > Thanks, > > Jere > 90 GL > 88 GL > |
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