Date:         Sun, 25 Nov 2001 11:24:43 -0800
Reply-To:     Matthew Pollard <poll7356@UIDAHO.EDU>
Sender:       Vanagon Mailing List <vanagon@gerry.vanagon.com>
From:         Matthew Pollard <poll7356@UIDAHO.EDU>
Subject:      Re: Help with a trig function
Comments: To: Jere Hawn <jbrschawn@EARTHLINK.NET>
In-Reply-To:  <LPBBJLCMHJOPCLHMMFECOELPDFAA.jbrschawn@earthlink.net>
Content-Type: TEXT/PLAIN; charset=US-ASCII

Ok, i'll help out there-
1) how long is the bus (the hypothenuse)?

the height to raise the bus is like this
Height=(length of bus in inches)*sine(angle)

So for a bus that is 16' long and 15 degrees up...
16x12xsin(15)=49.6932"
(or -> 16' x 12" x .258819=49.6"=4.14'

this is 4'!
lets go backwards- lets rais the bus 30" instead... what angle?
sin(X)=30'/192"
sin^-1(30/192)=X
X=8.98degrees
-->sin^1 is the inverse sine. on a calculator is is usually shift-sin
(the funciton that is inverse of sine)

got it?
cheers
Matthew
SOH-CAH-TOA

Matthew Pollard          "Racing with the wind and flirting with death
Dept. Of Chemistry        So have a cup of coffee and catch your breath"
University of Idaho
www.uidaho.edu/~poll7356



On Sat, 24 Nov 2001, Jere Hawn wrote:

> Hi All,
>
> I'm improving my "bleeding the cooling system" flow chart and I am at the
> raise the front by 15 degrees.  Being very weak in trigonometry and
> spelling... how many inches does the front end need to come up to make 15
> degrees.
>
> Sorry I don't have the wheel base dimensions.
>
> Once I've finish with this one part it will be available for distribution
> for those wishing a copy please p-mail
>
> Thanks,
>
> Jere
> 90 GL
> 88 GL
>