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Date:         Fri, 7 Feb 2003 16:01:01 -0500
Reply-To:     David Brodbeck <gull@CYBERSPACE.ORG>
Sender:       Vanagon Mailing List <vanagon@gerry.vanagon.com>
From:         David Brodbeck <gull@CYBERSPACE.ORG>
Subject:      Re: Heater fuel pressure question
Comments: To: Eric Zeno <vw4x4@FYI.NET>
In-Reply-To:  <3E440394.C4C9B2F@fyi.net>
Content-Type: TEXT/PLAIN; charset=US-ASCII

On Fri, 7 Feb 2003, Eric Zeno wrote:

> Assuming the fuel has the > same weight as water,

Bad assumption. Gasoline = approx. 6 lbs per gallon. Water = approx 8 lbs. per gallon. (U.S. gallons)

> how high would it have to be?

Reaching back into my fluid power classes...

Pressure (psi) = height (feet) * density (lbs per cubic foot) / 144

Water is 62.4 lbs per cubic foot, so gasoline must be roughly 41.6.

Solving for height...

Pressure * 144 / density = height

So 3 * 144 / 41.6 = 10.4 feet

The bottom of your tank needs to be 10.4 feet above the heater for a minimum of 3 psi. The pressure will be a bit higher with a full tank, but not much. Anyone want to check my math?

_ _ __ _ _ _| | | | David M. Brodbeck (N8SRE) Ypsilanti, MI / _` | | | | | | +----------------------------------------------------- | (_| | |_| | | | @ cyberspace.org \__, |\__,_|_|_| "To the optimist, the glass is half full. To the |___/ pessimist, the glass is half empty. To the engineer, the glass is twice as big as it needs to be."


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