Date:         Fri, 7 Feb 2003 23:12:45 -0500
Reply-To:     EMZ <vw4x4@FYI.NET>
Sender:       Vanagon Mailing List <vanagon@gerry.vanagon.com>
From:         EMZ <vw4x4@FYI.NET>
Subject:      Re: Heater fuel pressure question
Comments: To: David Brodbeck <gull@CYBERSPACE.ORG>
In-Reply-To:  <Pine.SUN.3.96.1030207155333.22651B-100000@grex.cyberspace.org>
Content-Type: TEXT/PLAIN; charset=US-ASCII

10 ft is out of the question.... even 6 ft is out of the van. I'll
have to stick to the fuel pump.

            Eric                   86-VW4x4
            vw4x4@fyi.net          86-SS Syncro
            Pittsburgh, PA USA     1936-Chrysler
                                   92-Jetta GWC
            www.fyi.net/~vw4x4/vw4x4.htm

On Fri, 7 Feb 2003, David Brodbeck wrote:

> On Fri, 7 Feb 2003, Eric Zeno wrote:
>
> > Assuming the fuel has the
> > same weight as water,
>
> Bad assumption.  Gasoline = approx. 6 lbs per gallon.  Water = approx 8
> lbs. per gallon.  (U.S. gallons)
>
> > how high would it have to be?
>
> Reaching back into my fluid power classes...
>
> Pressure (psi) = height (feet) * density (lbs per cubic foot) / 144
>
> Water is 62.4 lbs per cubic foot, so gasoline must be roughly 41.6.
>
> Solving for height...
>
> Pressure * 144 / density = height
>
> So 3 * 144 / 41.6 = 10.4 feet
>
> The bottom of your tank needs to be 10.4 feet above the heater for a
> minimum of 3 psi.  The pressure will be a bit higher with a full tank, but
> not much.  Anyone want to check my math?
>
>              _ _
>   __ _ _   _| | |  | David M. Brodbeck (N8SRE)              Ypsilanti, MI
>  / _` | | | | | |  +-----------------------------------------------------
> | (_| | |_| | | | @ cyberspace.org
>  \__, |\__,_|_|_| "To the optimist, the glass is half full.  To the
>  |___/             pessimist, the glass is half empty.  To the engineer,
>                    the glass is twice as big as it needs to be."
>