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Date:         Sun, 20 Mar 2005 01:45:02 -0600
Reply-To:     Al and Sue Brase <albeeee@MCHSI.COM>
Sender:       Vanagon Mailing List <vanagon@gerry.vanagon.com>
From:         Al and Sue Brase <albeeee@MCHSI.COM>
Subject:      Re: CV joint theory: long
Comments: To: jbange <hfinn@INGRATES.NET>
In-Reply-To:  <6.2.1.2.2.20050319204526.03cf92b0@66.51.205.14>
Content-Type: text/plain; charset=ISO-8859-1; format=flowed

Indeed! When one axle travels faster than the other, the differential (case and diff pinion shafts, and therefore the ring gear) splits the difference, iow, the speed is halfway between the two The force applied to each HAS to be the same, because the differential is not locked. Therfore the wear should be approximateely equal on the CV's. (not the tires, though!) Al Brase

jbange wrote:

>> The Differential (Rear Wheel Drive) >> This animation demonstrates how the power from the drive shaft turns the >> ring gear, which is fastened to the spider gear carrier. As the >> spider gears >> turn, they force the drive axle gears to turn as well. But if one wheel >> wants to go faster (such as when turning), the spider gears turn on >> their >> own axles, allowing each drive axle gear to turn at its own rate. > > > Ja, but if both the left and right drive axle gears are riding on the > spider gears, why would the right be taking all the work? Wouldn't it > balance evenly? Isn't that what the differential does? >


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