> Am I right in assuming that on a 4-stroke engine like this, the TDC > mark on the pulley turns at the speed of the crankshaft, so there are > only two possibiilties (either correct, or 180 degrees off)? To clarify: By "180" I meant the distributor drive shaft would be 180 degrees off. The crank would be 360 from TDC (i.e. TDC, but on on the intake stroke rather than power stroke). The distributor drive runs at 1/2 crank speed, yes? |
Please note - During the past 17 years of operation, several gigabytes of
Vanagon mail messages have been archived. Searching the entire collection
will take up to five minutes to complete. Please be patient!
Return to the archives @ gerry.vanagon.com
The vanagon mailing list archives are copyright (c) 1994-2011, and may not be reproduced without the express written permission of the list administrators. Posting messages to this mailing list grants a license to the mailing list administrators to reproduce the message in a compilation, either printed or electronic. All compilations will be not-for-profit, with any excess proceeds going to the Vanagon mailing list.
Any profits from list compilations go exclusively towards the management and operation of the Vanagon mailing list and vanagon mailing list web site.