Date:         Fri, 9 Nov 2007 19:00:36 -0500
Reply-To:     Mike S <mikes@FLATSURFACE.COM>
Sender:       Vanagon Mailing List <vanagon@gerry.vanagon.com>
From:         Mike S <mikes@FLATSURFACE.COM>
Subject:      Re: 12v relay help
Comments: To: Dug Smith <dug@DUGBERT.COM>
In-Reply-To:  <000f01c82326$a3b77da0$6601a8c0@Stimpy>
Content-Type: text/plain; charset="us-ascii"; format=flowed

At 06:17 PM 11/9/2007, Dug Smith wrote...
>So I figured what I needed was a relay.  Well, two actually, as the
>lock
>actuator is triggered by reversing the polarity of the electrickery
>going to
>it.  It's wired like the "Actuators / Reverse Polarity" setup in:
>http://www.the12volt.com/doorlocks/page3.asp#arp

If I understand correctly, there is a single solenoid in the
aftermarket lock, with 2 wires going to it, and the polarity is one way
for lock, the other for unlock?

It probable that both outputs are normally near ground, and providing
voltage to one or the other to operate the solenoid. If that's the
case, then both of your relays are normally energized, which is the
current draw you see.

With a Bosch relay, the coil is between terminals 85 and 86. Try moving
those connections from +12V to ground (the two center ones in the
diagram). Leave the terminal 87 connections to +12V. That will also
reverse the logic, so you'll also have to swap either the terminal 30s
between the relays, or swap the "alarm lock outputs" to the other
terminals 85/86 (the outer ones in the diagram).