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Date:         Mon, 19 Apr 2010 16:46:40 -0600
Reply-To:     Tom Buese <tombuese@COMCAST.NET>
Sender:       Vanagon Mailing List <vanagon@gerry.vanagon.com>
From:         Tom Buese <tombuese@COMCAST.NET>
Subject:      Re: Why go to big tires?
Comments: To: Sudhir Desai <sudhir.desai@GMAIL.COM>
In-Reply-To:  <l2l5c80974c1004191532lda28759br59b2709a00b33b14@mail.gmail.com>
Content-Type: text/plain; charset=US-ASCII; format=flowed; delsp=yes

On Apr 19, 2010, at 4:32 PM, Sudhir Desai wrote: > ................... > > (as far as tire/wheel combinations go, you can always get a lighter > wheel to somewhat offset the heavier tire. the stock steelies are > pretty heavy, as are the stock alloys)

& you forgot to calculate what brand of tires we should use & whether the whitewall is on the inside or outside! LOL!

YMMV,

Mr. BZ-less is more > > > > I'm not going to offer to do the actual calculations, as I'm sure > there is a solid modeler out there that could do ALL of them > correctly. (I had to rewrite that email four times because of bad math > on my part) ;) > Sudhir > > > > On Mon, Apr 19, 2010 at 18:07, Jake de Villiers > <crescentbeachguitar@gmail.com> wrote: >> Nice explanation Suds but... you've left out the other half of the >> equation. >> >> As the wheel diameter grows the weight of the wheel also grows, >> especially >> the tire mounting section which is at the far end of the 'lever' >> system >> which is the tire's diameter. >> >> So that 5600in/lbs is no longer sufficient to stop the more massive >> rotating >> 'lever', you need even more brakes. >> >> On Mon, Apr 19, 2010 at 2:39 PM, Sudhir Desai >> <sudhir.desai@gmail.com> >> wrote: >>> >>> Sorry about the simplicity, I figured I would gloss it over >>> HARDCORE. >>> >>> the 0 represents the hub, the ) the brake rotor/drum, the | the >>> outside of the tire. >>> >>> >>> STOCK >>> distance of force from hub: >>> 0--5"----//---12.5" >>> >>> direction of force: >>> 0--up-------down >>> >>> illustration: >>> 0--)-----//----| >>> >>> lets say the car is rolling along, and the torque needed to stop the >>> wheels abruptly (ignoring/subtracting any sort of rotational >>> inertia, >>> and friction, etc) is 5000in-lb. >>> >>> that means, we would have to exert a force of 5000in-lb/12.5in = >>> 400lb >>> (at 12.5" out from the hub) to stop the wheels abruptly. >>> >>> now, we go in more to where we can stop the wheels, the brakes. at >>> 5" >>> out from the hub, that 400lb force needed is now (400lb*12.5in) = >>> (xlb*5in), or x = ((400lb*12.5")/5"), so >>> >>> x = (5000in-lb)/5" = 1000lb >>> >>> >>> SO... to stop the wheel abruptly, we need 1000lb of force at 5" out >>> from the hub, and that's the torque our stock brakes can put out. >>> >>> >>> >>> when we increase the tire size to a 28" tire: >>> >>> OVERSIZE >>> distance of force from hub: >>> 0--5"----//---14" >>> >>> direction of force: >>> 0--up-------down >>> >>> illustration: >>> 0--)-----//----| >>> >>> >>> >>> SO NOW WE GO BACKWARDS!!!! lol~ >>> due to our original assumption of 1000in-lb, >>> we have just increased the diameter of our tires to 28". >>> >>> this means that our 1000 lb force (5000in-lb) that was enough to >>> stop >>> the 25" tire will not be enough to stop a 28 inch tire by the >>> following equation. >>> >>> 5000in-lb/12.5in = xin-lb/14in, or xin-lb = (5000in-lb*14in)/12.5in >>> >>> x=(5000*14)/12.5 = 5600in-lb is our new stopping torque needed. >>> >>> our stock brakes can only exert 1000in-lb of torque, so we won't be >>> able to stop the wheel abruptly anymore. >>> >>> hopefully y'all are following me still... >>> we just increased the amount of force needed to stop the wheels, and >>> we see that our stock brakes are not enough to do so. >>> >>> NOW, we need to calculate the size of brakes we need to stop the >>> tire >>> abruptly (ignoring all other factors). >>> >>> we take the known stopping torque, and our original brakes (10" >>> brakes >>> LOL), and see how that compares with our new 5600in-lb >>> x-in/5600in-lb = 5in/5000in-lb >>> >>> x = (5*5600)/5000 = 5.6in >>> >>> >>> >>> so we'd need 11.2" diameter brakes to put out the 5600in-lb torque >>> needed to stop the wheels abruptly. >>> >>> which is another inch diameter of brake needed. >>> >>> >>> I hope my simple explanation (with calculations to show i wasn't >>> just >>> pulling numbers out of the air) was satisfactory. :) >>> >>> Sudhir >> >> >> >> -- >> Jake >> >> 1984 Vanagon GL 1.9 WBX 'The Grey Van' >> 1986 Westy Weekender/2.5 SOHC Suby 'Dixie' >> >> Crescent Beach, BC >> >> www.thebassspa.com >> www.crescentbeachguitar.com >> http://subyjake.googlepages.com/mydixiedarlin%27 >> >>


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