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Date:         24 May 1996 09:57:25 -0700
Sender:       Vanagon Mailing List <vanagon@vanagon.com>
From:         "Harvey Chao" <Harvey_Chao@smtp.svl.trw.com>
Subject:      F.Y.I. - regulating chargin

5/24/96 9:21 AM F.Y.I. - regulating charging current (long)

There have been a few recent messages about excessive current when recharging a depleated axu. battery so as not to blow the wiring or alternator.

One suggestion was adding resistors to the charging circuit.

I think that there is a better (mre elegant)solution. Perhaps some of you out there can confirm this for me as it has been just a "few"years since I was in school on this topic.

If I recall, the charging rate of a battery is determined by (the difference in voltage between the battery under charge and the applied voltage) and by the internal resistance of the battery. In theory, if the difference (delta v) is high enough, and the source is an ideal unlimited source, you can pour unlimited current into the battery until it boils and explodes and or melts the wiring and itself. This is because the internal resistance of a healthy battery is very low where the only limiting factor is this internal resistance of the battery. [Note - a bad battery, one that is "sulfated" and won't accept a charge - has a very high internal resistance, that's why it won't accept any significant current flow when you put a nominal 14 or so charging voltage across it]

Think of a battery as a very low value resistance in series with an imaginary "perfect" source of unlimited current . As such, the only thing that limits the amount of discharge amps in a direct short is the value of this internal resistance. Since we know that a direct short can produce 100s of amps at a nominal 11-12 volts the internal resistance is very very low (amps = volts/resistance - so if amps is really big, and volts is around 12, then resistance is on the order of 0.1 ohms or less.)

Let's say that the alternator output is regulated to 14 volts up to the rated output of the alternator (the voltage will start to drop off after that max output current), and that the open circuit voltage of the discharged battery to be recharged is 10 volts. OHm's law says current = volts/ohms => (14-10)/0.1 = 40, using a very conservative 0.1 ohm value of internal resistance, it could easily be 0.05 or less which would double the current to 80 amps or more.

We can't do anything about the internal resistance of the battery under charge, but we can limit the applied voltage and thus reduce the delta v.

Automotive chargint circuits apply a constant voltage to the battery and allow the current to vary with the state of charge of the battery - really high at first (max delta v) and then tapering as the voltage of the battery under charge rises with it's state of charge. Adjustable voltage regulators for alternators are available - I used to have one on one of my cars. The crude implementation is to manually lower the alternator output voltage by resetting the variable regulator's adjustment setting with a screwdriver. Just gotta remember to put it back after the battery gets abeyond it's initial high current surge at the start of the recharge cycle.

I am sure that it is possible to take a standared regulator, "gut" it so that the physical carrier for the alternator brushes remains, and bring the leads out to a seperate regulator circuit that is dual mode, 1) under "normal" loads it regulates as a stock regulator, by only regulating the output voltage of the alternator at around 14 volts. It will have a second function 2) whereby it senses the output level of the alternator current, and when the current approaches a preselt limit (alternator rating) it reduces the voltage regulation from 14 to some lessor value so that the current output does not exceed rating. Any "takers" on this out there???

[I know that existing standard circuts will tend to be self limiting and do this to a degree - as the current approaches max, the voltage drops, but the standard regulator keeps trying to keep the voltage up and so the alternator runs "wide open" limited only by resistance losses in it's windings and diodes. The problem is that it keeps trying to supply more current than it is rated at. When the current goes beyound rated value, and the resistance of the windings and diodes are fixed, there is increased heat generated in those items (amps X amps x resistance) due to the current flow that is above limit - that's when diodes blow and windings melt.]


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