Date:         Fri, 26 Jul 1996 16:14:02 -0400
Sender:       Vanagon Mailing List <vanagon@vanagon.com>
From:         DHaynes57@aol.com
Subject:      Re: basic electronics question

In a message dated 96-07-26 15:33:14 EDT,
fairwind@northernnet.com (Dan Houg) writes:

<< 
 question:
 
 i have a super bright , jumbo LED that reqires 2.6v @ 50ma
 
 how do i figure the resistance of the dropping resistor for a 12v 
 source? >>


R = I/E       Need to drop 10 volts at 50mA.           10 / .050  =  200
ohms.

For power, watts = volts X amps.    10 volt X  ..050 amp = .5.  

you need a 200 ohm, 1/2 wat resistor.  I would go with a 1 watt to be safe.

Dennis H.

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